Hallo Flo,
Ja, Beispiel:
\( A= \left( \begin{array}{rr} 1 & 1 \\ 0 & 1\end{array}\right), b=\left(\begin{array}{c} 1 \\ 0 \end{array}\right) \)
Dann gilt:
\( A*b=\left(\begin{array}{rr} 1 & 1 \\ 0 & 1\end{array}\right)*\left(\begin{array}{c} 1 \\ 0 \end{array}\right)=\left(\begin{array}{c} 1 \\ 0 \end{array}\right) \)
Aber:
\( A'*b=\left(\begin{array}{rr} 1 & 0 \\ 1 & 1\end{array}\right)*\left(\begin{array}{c} 1 \\ 0 \end{array}\right)=\left(\begin{array}{c} 1 \\ 1 \end{array}\right) \)
s1k
Student, Punkte: 225