Hallo!
\(\displaystyle 3^{3n+2}\cdot 3\cdot 2^3\cdot x^{4n-3}\cdot x^{1-6n} = 3^{3(n+1)}\cdot 2^3\cdot x^{-2(n+1)} = 8\cdot\left(\frac{27}{x^2}\right)^{n+1}\).
Gruß.
Sonstiger Berufsstatus, Punkte: 1.57K
Hallo!
\(\displaystyle 3^{3n+2}\cdot 3\cdot 2^3\cdot x^{4n-3}\cdot x^{1-6n} = 3^{3(n+1)}\cdot 2^3\cdot x^{-2(n+1)} = 8\cdot\left(\frac{27}{x^2}\right)^{n+1}\).
Gruß.