\(f'(x)=\left[\dfrac{x^3}{4} \right]' - \left[ 2\right]'=\dfrac{1}{4}\left[x^3 \right]' - \left[ 2\right]' = \dfrac{3x^2}{4}\)
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\(f'(x)=\left[\dfrac{x^3}{4} \right]' - \left[ 2\right]'=\dfrac{1}{4}\left[x^3 \right]' - \left[ 2\right]' = \dfrac{3x^2}{4}\)