Über den Logarithmus:
\(K_0 = K_n\cdot q^n \quad|:K_n\)
\(q^n = \frac{K_0}{K_n}\quad|\ln\)
\(\ln(q^n) = \ln\left(\frac{K_0}{K_n}\right)\)
\(n\cdot \ln(q) = \ln\left(\frac{K_0}{K_n}\right)\)
\(n = \frac{\ln\left(\frac{K_0}{K_n}\right)}{\ln(q)}\)
Punkte: 8.88K
Gerne. ─ orthando 05.12.2019 um 16:44