Hallo,
\(\begin{equation} \begin{split}\dfrac{4a}{4x-1}&= \dfrac{2b}{3a} \\
\dfrac{4a}{4x-1} \cdot (4x-1)&= \dfrac{2b}{3a} \cdot (4x-1)\\
4a &= \dfrac{2b}{3a}(4x-1)\\
\dfrac{4a\cdot 3a}{2b}&=4x-1\\
1+ \dfrac{6a^2}{b}&= 4x \\
\dfrac{6a^2+b}{4b}&=x \end{split}\end{equation}\)
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