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\(\frac{1}{\lambda^2} + \frac{1}{4\lambda^2}-5 = 0\)
\(\frac{1}{\lambda^2} + \frac{1}{4\lambda^2}= 5\)
\(\frac{4}{4\lambda^2} + \frac{1}{4\lambda^2}= 5\)
\(\frac{5}{4\lambda^2} = 5\)
\(\frac{1}{4\lambda^2} = 1\)
\(\frac{1}{4} = \lambda^2\)
\(\pm \frac{1}{2} = \lambda\)
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Student, Punkte: 350
Student, Punkte: 350