Hier musstt du partiell integrieren
\(\int f'g=fg-\int fg'\)
\(g=x\)
\(g'=1\)
\(f'=e^{3x+2}\)
\(f=\frac{1}{3}e^{3x+2}+C\)
\(\int xe^{3x}dx=\frac{1}{3}xe^{3x+2}-\frac{1}{3}\int e^{3x+2}dx+C=\frac{1}{3}xe^{3x+2}-\frac{1}{9}e^{3x+2}+C=\frac{(3x-1)e^{3x+2}}{9}+C\)
Student, Punkte: 2.44K
LG Josh ─ anonymf7840 03.05.2020 um 17:46
LG Josh ─ anonymf7840 03.05.2020 um 17:46