\(\sqrt{\left(\dfrac{-3}{2}\right)^2 -1} = \sqrt{2.25 -1} = \sqrt{1.25}\)
\(\dfrac{3}{2} \pm \sqrt{1.25} = \dfrac{3}{2} \pm \dfrac{2\sqrt{1.25}}{2} = \dfrac{3 + 2\sqrt{1.25}}{2} = \dfrac{3 + \sqrt{1.25 \cdot 2^2}}{2}=\dfrac{3 + \sqrt{5}}{2} \)
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